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what is the strength of the electric field at the position indicated by the dot in (figure 1)?
1. what is the strength of the electric field at the position indicated by the dot in (figure 1)? Quiz answer
Correct Answer: E=kq/r^2
r= 5 x root2 = 7.07 cm or .0707 m (property of 45-45-90 right triangle)
E=(9 x 10^9)(1 x 10^-9)/(.0707)^2
= 1800.5 N/C
Now to find the x component,
cos 45 = x/1800.5
x= 1273.18 N/C
Now just multiply by 2 to accommodate both charges,
E=2546.35 N/C in direction of 0 degrees (no y component since they cancel each other out)
Explanation:what is the strength of the electric field at the position indicated by the dot in (figure 1)?
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